React - Change the button color onClick
In this tutorial, we are going to learn about how to change the color of a button onClick in React.
Consider, we have the following component in our react app:
import React from 'react';
function Home(){
return (
<div className="center">
<button>SignUp</button>
</div>
)
}
export default Home;To change the button color in React, add the onClick event handler to it and change the color conditionally whenever a button is clicked.
Here is an example:
import React, { useState } from "react";
function Home() {
const [active, setActive] = useState(false);
const handleClick = () => {
setActive(!active);
};
return (
<div className="center">
<button
onClick={handleClick}
style={{ backgroundColor: active ? "black" : "white" }}
>
SignUp
</button>
</div>
);
}
export default Home;In the example above, we added a handleClick event handler to the onClick prop and state active to the style property, so whenever a button is clicked it runs the handleClick function and changes the active state from false to true or vice versa.
Based on the active state we are changing the button background Color using ternary expression.
{backgroundColor: active ? "black" : "white" }If active is false it chooses white color, if its true it chooses black color.
If you are styling your button using css classes you change it between two classnames like this:
Here is an example:
import React, { useState } from "react";
function Home() {
const [active, setActive] = useState(false);
const handleClick = () => {
setActive(!active);
};
return (
<div className="center">
<button
onClick={handleClick}
className={active ? "black-btn" : "white-btn"}
>
SignUp
</button>
</div>
);
}
export default Home;In the example above, if active state is true it chooses black-btn class, if active state is false it chooses white-btn class.
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