Checking if variable is a integer in Python

In this tutorial, we are going to learn about how to check if the variable is a integer in Python with the help of examples.

Consider, that we have the following variable in our code:

age = 24

Now, we need to check whether the above variable is a int or not.

Using type() function

To check if a variable is a integer or not, we can use the built-in type() function in Python.

The type() function takes the variable as an argument and returns the type of the following object.

Here is an example:

age = 24

if type(name) == int:
    print('Variable is a integer')
else:
    print('Variable is not a integer')

Output:

'Variable is a integer'

In the above code,

1. We have first initialized the variable with a integer.

2. Then we used the equality == operator to check if both values refer to the same object.

If it returns True then it prints the variable is a integer, if the variable is not a integer then it returns False and prints Variable is not a integer.

Another example:

age = "23"

if type(age) == int:
    print('Variable is integer')
else:
    print('Variable is not a integer')

Output:

'Variable is not a integer'

Instead of equality operator, we can also use the is operator like this.

age = 24

if type(age) is str:
    print('Variable is a integer')
else:
    print('Variable is not a integer')

Using isinstance() function

Alternatively, we can also use the isinstance() function in Python to check if a given variable is a integer.

The isinstance() function takes the two arguments, the first argument is object, and the second argument is type then It returns True if a given object is a specified type otherwise it returns False.

age = 24

if  isinstance(name, int):
    print('Variable is a integer')
else:
    print('Variable is not a integer')