Author -  Sai gowtham

TypeError:$(document).ready is not a function in jQuery [Solved]

In this tutorial, we are going to learn about how to solve the TypeError: $(document).ready is not a function in jQuery.

The “TypeError: $(document).ready is not a function” in jQuery error occurs one of the following reasons:

  • Initializing the jQuery library after the JavaScript code.

  • Using the jQuery library without adding to the HTML file.

  • Using the second set of paranthesis () after the calling the ready() method.

  • Overriding the $ symbol or jQuery variables in your code.

Here is an example, how the error occurs:

$(document).ready(function(){
    console.log('hello jquery');
})();

Output:

Uncaught TypeError: $(...).ready(...) is not a function

In the above example, we have got the error because we are using the extra paranthesis () after the ready() method.

To solve the “TypeError: $(document).ready is not a function” in jQuery, remove the paranthesis after the ready method and makesure to run the JavaScript code after the jQuery library initialization.

Here is an example, how to fix the error:

$(document).ready(function(){
    console.log('hello jquery');
});

The order of loading the jQuery library and JavaScript file is important while working with jQuery.

  • First jQuery library.

  • JavaScript file.

<!DOCTYPE html>
<html lang="en">
  <head>
    <meta charset="UTF-8" />
    <title>Loding jquery</title>
  </head>

    <body>

   <h1>Good morning</h1>

  <!-- Your jQuery library -->
   <script
      src="https://code.jquery.com/jquery-3.6.3.min.js"
      integrity="sha256-/xUj+3OJU5yExlq6GSYGSHk7tPXikynS7ogEvDej/m4="
      crossorigin="anonymous"
    ></script>

    <!-- Your JS script file goes here -->
    <script src="app.js"></script>
    </body>
</html>

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